Isomorphic Strings C++ Code

Given two strings s and t, determine if they are isomorphic.

Two strings s and t are isomorphic if the characters in s can be replaced to get t.

All occurrences of a character must be replaced with another character while preserving the order of characters. No two characters may map to the same character, but a character may map to itself.

This if statement checks whether the lengths of s and t are equal. If not, it returns false because the two strings cannot be isomorphic.

These two lines declare two unordered maps: sToT and tToS. These maps are used to store the mappings between characters in s and their corresponding characters in t, and between characters in t and their corresponding characters in s, respectively.

These two lines declare two char variables, c1 and c2, and assign them the values of the ith characters in s and t, respectively.

This if statement checks whether c1 is already mapped to a character in t in sToT, and whether c2 is already mapped to a character in s in tToS. If both maps do not contain a mapping for the characters, the function creates new mappings in both maps. Otherwise, the function checks whether the existing mappings in both maps match the current characters. If any of these conditions is not met, the function returns false.

This line closes the for loop. If the function completes the loop without finding any inconsistencies between the maps, it returns true to indicate that the two strings are isomorphic.

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